BOUNDARY LAYER THICKNESS:
Boundary layer thickness at distence x from leading edge is
S = (4.64×x/Rex^(1/2))
Here Rex is Reynolds number at distence x from leading edge.
Rex=PLxV/u
Where P=density of the fluid
Lx=distence from leading edge
V=velocity of fluid
u=Dynamic viscosity of the fluid
If all variables are kept unchanged then
*Boundary layer thickness (s) is directly proportional to root of Lx(distence from leading edge)
Example question:
Q1)
Solution
Since, boundary layer thickness is directly proportional to square root of distence from leading edge.
Where
S1(2mm) is boundary layer thickness at distence Lx1(2m) from leading edge
S2(? ) Boundary layer thickness at Lx2(4m)
So
(S1/S2)=(Lx1/Lx2)^(1/2)
(2/S2)=(2/4)^(1/2)
S2=2×2^(1/2)
S2=2×1.414
S2=2.828mm.(answer)
So option (B) is right answer.
Boundary layer thickness is over but, relation between Hydrodynamic boundary layer thickness and thermal boundary layer thickness will be updated very soon.
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By RAJKUMAR CLASSES
Boundary layer thickness at distence x from leading edge is
S = (4.64×x/Rex^(1/2))
Here Rex is Reynolds number at distence x from leading edge.
Rex=PLxV/u
Where P=density of the fluid
Lx=distence from leading edge
V=velocity of fluid
u=Dynamic viscosity of the fluid
If all variables are kept unchanged then
*Boundary layer thickness (s) is directly proportional to root of Lx(distence from leading edge)
Q1)
Solution
Since, boundary layer thickness is directly proportional to square root of distence from leading edge.
Where
S1(2mm) is boundary layer thickness at distence Lx1(2m) from leading edge
S2(? ) Boundary layer thickness at Lx2(4m)
So
(S1/S2)=(Lx1/Lx2)^(1/2)
(2/S2)=(2/4)^(1/2)
S2=2×2^(1/2)
S2=2×1.414
S2=2.828mm.(answer)
So option (B) is right answer.
Boundary layer thickness is over but, relation between Hydrodynamic boundary layer thickness and thermal boundary layer thickness will be updated very soon.
By RAJKUMAR CLASSES




Sir this topic is very useful. Sir send from starting to end of FM
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